The time periods of two simple pendulums at a place are in the ratio 2 :1. What will be the corresponding ratio of their lengths? - Physics

The time periods of two simple pendulums at a place are in the ratio 2:1. What will be the corresponding ratio of their lengths?

Sum

T₁ : T₂ = 2 : 1

But since T α `sqrt(l)`

So

`"T"_1/"T"_2=sqrt(l1)/sqrt(l2)=2/1`

`(l1)/(l2)=(2xx2)/(1xx1)`

`=4/1`

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