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Question
The total surface area of a hollow cylinder which is open from both sides is 4620 sq. cm,area of base ring is 115.5 sq. cm and height 7 cm. Find the thickness of the cylinder
Solution
Let the inner radii of hollow cylinder rcm
Outer radii of hollow cylinder Rcm
Then,
`2πrh + 2πRh +2πR^2 - 2πr^2 = 4620 → (1)`
`πR^2 =πr^2 =115.5→(2)`
`⇒ 2πh(R+r)+2(πR^2-πr^2)=4620 and πR^2-m^2 = 115.5`
`⇒2πh(R+r)+231=4620 and π(R^2-r^2)=115.5`
`⇒2π× 7(r+R)=4389 and π(R^2-r^2)=115.5`
`⇒π (R+r)=313.5 and π (R+r) (R-r)=115.5`
`⇒(π(R+r)(R-r))/(π(R+r))=115.5/313.5`
`⇒ R-r=7/19cm`.
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