Question

The value of `int_-1^1|x|` dx is ______.

Options

• –2

• –1

• 1

• 2

Answer 1

The value of `int_-1^1|x|` dx is 1.

Explanation:

`int_-1^1 |x|dx= int_-1^0 -x dx + int_0^1x  dx`

= `-[x^2/2]_-1^0+[x^2/2]_0^1`

= `-[(0)^2/2-(-1)^2/2]+[(1)^2/2-(0)^2/2]`

= `- [0-1/2]+[1/2 - 0]`

= `1/2+1/2`

= 1