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There are 15 tickets in a box, each bearing one of the numbers from 1 to 15. One ticket is drawn at random from the box. Find the probability of event that the ticket drawn - Algebra

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Question

There are 15 tickets in a box, each bearing one of the numbers from 1 to 15. One ticket is drawn at random from the box. Find the probability of event that the ticket drawn - shows a number which is a multiple of 5.

Sum

Solution

Sample Space (S) = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15}
∴ n(S) = 15

Event B: the ticket shows  a number which is a multiple of 5
B = {5, 10, 15 }
∴ n(B) = 3 

∴ P (B) = `"n(B)"/"n(S)" =3/15 =1/5`​

Hence, the probability that the ticket shows  a number which is a multiple of 5 is `=1/5`​.

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Chapter 5: Probability - Practice Set 5.4 [Page 125]

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Balbharati Algebra (Mathematics 1) [English] 10 Standard SSC Maharashtra State Board
Chapter 5 Probability
Practice Set 5.4 | Q 3.2 | Page 125

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