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There are 15 tickets in a box, each bearing one of the numbers from 1 to 15. One ticket is drawn at random from the box. Find the probability of event that the ticket drawn - shows an even number. - Algebra

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Question

There are 15 tickets in a box, each bearing one of the numbers from 1 to 15. One ticket is drawn at random from the box. Find the probability of event that the ticket drawn - shows an even number.

Sum

Solution

Sample Space (S) = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15}

∴ n(S) = 15

Event A: the ticket shows an even number

A = {2, 4, 6, 8, 10, 12, 14}

∴ n(A) = 7 

∴ `P (A) = (n(A))/(n(S))`

= `7/15`

Hence, the probability that the ticket shows an even number is `7/15`.

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Chapter 5: Probability - Practice Set 5.4 [Page 125]

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Balbharati Algebra (Mathematics 1) [English] 10 Standard SSC Maharashtra State Board
Chapter 5 Probability
Practice Set 5.4 | Q 3.1 | Page 125

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