Advertisements
Advertisements
Question
Thirty children were asked about the number of hours they watched TV programmes in the previous week. The results were found as follows:-
1 | 6 | 2 | 3 | 5 | 12 | 5 | 8 | 4 | 8 |
10 | 3 | 4 | 12 | 2 | 8 | 15 | 1 | 17 | 6 |
3 | 2 | 8 | 5 | 9 | 6 | 8 | 7 | 14 | 12 |
(i) Make a grouped frequency distribution table for this data, taking class width 5 and one of the class intervals as 5 - 10.
(ii) How many children watched television for 15 or more hours a week?
Solution
(i) Our class intervals will be 0 − 5, 5 − 10, 10 −15…..
The grouped frequency distribution table can be constructed as follows.
Hours | Number of children |
0 − 5 | 10 |
5 − 10 | 13 |
10 − 15 | 5 |
15 − 20 | 2 |
Total | 30 |
(ii) The number of children who watched TV for 15 or more hours a week is 2 (i.e., the number of children in class interval 15 − 20).
APPEARS IN
RELATED QUESTIONS
The value of π up to50 decimal places is given below:-
3.14159265358979323846264338327950288419716939937510
(i) Make a frequency distribution of the digits from 0 to 9 after the decimal point.
(ii) What are the most and the least frequently occurring digits?
The monthly wages of 30 workers in a factory are given below:
83.0, 835, 890, 810, 835, 836, 869, 845, 898, 890, 820, 860, 832, 833, 855, 845, 804, 808,
812, 840, 885, 835, 836, 878, 840, 868, 890, 806, 840, 890.
Represent the data in the form of a frequency distribution with class size 10.
Thirty children were asked about the number of hours they watched T.V. programmers in the previous week. The results were found as follows:
1 | 6 | 2 | 3 | 5 | 12 | 5 | 8 | 4 | 8 |
10 | 3 | 4 | 12 | 2 | 8 | 15 | 1 | 17 | 6 |
3 | 2 | 8 | 5 | 9 | 6 | 8 | 7 | 14 | 12 |
(i) Make a grouped frequency distribution table for this data, taking class width 5 and one of the class intervals as 5 – 10.
(ii)How many children watched television for 15 or more hours a week?
The marks scored by 55 students in a test are given below:
Marks | 0-5 | 5-10 | 10-15 | 15-20 | 20-25 | 25-30 | 30-35 |
No. of students | 2 | 6 | 13 | 17 | 11 | 4 | 2 |
Prepare a cumulative frequency table:
The number of books in different shelves of a library are as follows:
30, 32, 28, 24, 20, 25, 38, 37, 40, 45, 16, 20
19, 24, 27, 30, 32, 34, 35, 42, 27, 28, 19, 34,
38, 39, 42, 29, 24, 27, 22, 29, 31, 19, 27, 25
28, 23, 24, 32, 34, 18, 27, 25, 37, 31, 24, 23,
43, 32, 28, 31, 24, 23, 26, 36, 32, 29, 28, 21.
Prepare a cumulative frequency distribution table using 45-49 as the last class interval.
Given below is a cumulative frequency distribution table showing the ages of people living in a locality:
Ace in years | No. of persons |
Above 108 | 0 |
Above 96 | 1 |
Above 84 | 3 |
Above 72 | 5 |
Above 60 | 20 |
Above 48 | 158 |
Above 36 | 427 |
Above 24 | 809 |
Above 12 | 1026 |
Above 0 | 1124 |
Prepare a frequency distribution table
Mark the correct alternative in each of the following: Tally marks are used to find
For drawing a frequency polygon of a continous frequency distribution, we plot the points whose ordinates are the frequencies of the respective classes and abcissae are respectively ______.
30 children were asked about the number of hours they watched TV programmes last week. The results are recorded as under:
Number of hours | 0 – 5 | 5 – 10 | 10 – 15 | 15 – 20 |
Frequency | 8 | 16 | 4 | 2 |
Can we say that the number of children who watched TV for 10 or more hours a week is 22? Justify your answer.
Convert the given frequency distribution into a continuous grouped frequency distribution:
Class interval | Frequency |
150 – 153 | 7 |
154 – 157 | 7 |
158 – 161 | 15 |
162 – 165 | 10 |
166 – 169 | 5 |
170 – 173 | 6 |
In which intervals would 153.5 and 157.5 be included?