English
Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 8

Three identical coins, each of diameter 6 cm are placed as shown. Find the area of the shaded region between the coins. (π = 3.14) (3=1.732) - Mathematics

Advertisements
Advertisements

Question

Three identical coins, each of diameter 6 cm are placed as shown. Find the area of the shaded region between the coins. (π = 3.14) `(sqrt(3) = 1.732)`

Sum

Solution

Given diameter of the coins = 6 cm

∴ Radius of the coins = `6/2` = 3 cm

Area of the shaded region = Area of equilateral triangle – Area of 3 sectors of angle 60°

Area of the equilateral triangle = `sqrt(3)/4  "a"^2  "units"^2`

= `sqrt(3)/4 xx 6 xx 6  "cm"^2`

= `(1.732)/4 xx 6 xx 6  "m"^2` 

= 15.588 cm

Area of 3 sectors =  `3 xx theta/(360^circ) xx pi"r"^2  "sq.units"`

= `3 xx (60^circ)/(360^circ) xx 3.14 xx 3 xx 3  "cm"^2`

= 1.458 cm2

∴ Area of the shaded region = 15.588 – 14.13 cm2 

= 1.458 cm2

Required area = 1.458 cm2 ...(approximately)

shaalaa.com
Area of the Sector
  Is there an error in this question or solution?
Chapter 2: Measurements - Exercise 2.4 [Page 72]

APPEARS IN

Samacheer Kalvi Mathematics [English] Class 8 TN Board
Chapter 2 Measurements
Exercise 2.4 | Q 7 | Page 72
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×