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Question
Three identical coins, each of diameter 6 cm are placed as shown. Find the area of the shaded region between the coins. (π = 3.14) `(sqrt(3) = 1.732)`
Solution
Given diameter of the coins = 6 cm
∴ Radius of the coins = `6/2` = 3 cm
Area of the shaded region = Area of equilateral triangle – Area of 3 sectors of angle 60°
Area of the equilateral triangle = `sqrt(3)/4 "a"^2 "units"^2`
= `sqrt(3)/4 xx 6 xx 6 "cm"^2`
= `(1.732)/4 xx 6 xx 6 "m"^2`
= 15.588 cm2
Area of 3 sectors = `3 xx theta/(360^circ) xx pi"r"^2 "sq.units"`
= `3 xx (60^circ)/(360^circ) xx 3.14 xx 3 xx 3 "cm"^2`
= 1.458 cm2
∴ Area of the shaded region = 15.588 – 14.13 cm2
= 1.458 cm2
Required area = 1.458 cm2 ...(approximately)
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