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Question
Options
2Ω
4Ω
8Ω
16Ω
Solution
2Ω
Explanation:
According to meter bridge experiments, relationships use the null point finding technique.
The expression gives the condition of a null point in the meter bridge.
`R_a/R_b = L/(100 - L)` ....(1)
Here, L is the distance from one end of the bridge; that point is called a null point.
Substitute the value of Rb = 4Ω and L = 20 cm in equation 1.
`R_a/(4 Ω) = (20 " cm")/(100 " cm" - 20 " cm")`
`"R"_a/(4 Ω) = 20/80`
`"R"_a/(4 Ω) = 1/4`
`"R"_a = 1/4 xx 4Ω`
Ra = 1 Ω
But the bangle is connected toward the diametral end side of the apparatus system, so for the balanced condition.
`(R_("gold bengle"))/2 = R_a`
Ra = 1Ω Put the value on the above equation.
`(R_("gold bengle"))/2 = 1`
`R_("gold bengle") = 2 xx 1`
`R_("gold bengle")` = 2 Ω
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