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Two Alternate Sides of a Regular Polygon, When Produced, Meet at the Right Angle. Find: (I)The Value of Each Exterior Angle of the Polygon; (Ii) the Number of Sides in the Polygon. - Mathematics

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Question

Two alternate sides of a regular polygon, when produced, meet at the right angle.
Find:
(i)The value of each exterior angle of the polygon;
(ii) The number of sides in the polygon.

Sum

Solution

(i) Let the measure of each exterior angle is x and the number of sides is n.
Therefore we can write :
n = `(360°)/x`
Now We have
x + x + 90° = 180°
2x = 90°
x = 45°

(ii) Thus the number of sides in the polygon is :
n = `(360°)/(45°)` 
n = 8.

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Names of Polygons
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Chapter 14: Rectilinear Figures [Quadrilaterals: Parallelogram, Rectangle, Rhombus, Square and Trapezium] - Exercise 14 (A) [Page 169]

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Selina Concise Mathematics [English] Class 9 ICSE
Chapter 14 Rectilinear Figures [Quadrilaterals: Parallelogram, Rectangle, Rhombus, Square and Trapezium]
Exercise 14 (A) | Q 11 | Page 169
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