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Question
Two dice (each bearing numbers 1 to 6) are rolled together. Find the probability that the sum of the numbers on the upper-most faces of two dice is 7, 8 or 9.
Solution
When two dice are rolled, total number of possible outcomes = 36
Favorable outcomes for the sum of number 7, 8 or 9 are:
{(1, 6),(2, 5),(2, 6),(3, 4),(3, 5),(3, 6),(4, 3),(4, 4),(4, 5),(5, 2),(5, 3),(5, 4),(6, 1),(6, 2),(6, 3)}
Number of favorable outcomes = 15
P(getting a sum of 7, 8 or 9) = `15/36 = 5/12`
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