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Question
A bag contains 8 red, 6 white and 4 black balls. A ball is drawn at random from the bag. Find the probability that the drawn ball is Not black
Solution
Total no. of possible outcomes = 8 + 6 + 4 = 18 {8 red, 6 white, 4 black}
E โถ event of getting no black ball
No. of favourable outcomes = 4 {4 black balls}
Probability, P(E) =`"No.of favorable outcomes"/"Total no.of possible outcomes"`
P(E) = 4/18 = 2/9
(`barE`) โถ ๐๐ฃ๐๐๐ก ๐๐ ๐๐๐ก ๐๐๐ก๐ก๐๐๐ ๐๐๐๐๐ ๐๐๐๐
P(`barE`) = 1 − ๐(๐ธ)
= 1 − 2/9 = 7/9
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