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Question
A bag contains 8 red, 6 white and 4 black balls. A ball is drawn at random from the bag. Find the probability that the drawn ball is Neither white nor black
Solution
E ⟶ event of getting neither white nor black.
No. of favourable outcomes = 15 – 6 – 4 = 8 {Total balls – no. of white balls – no.
of black balls}
Probability, P(E) =`"No.of favorable outcomes"/"Total no.of possible outcomes"`
P(E) = 8/18 = 4/9
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