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Question
Two different coins are tossed simultaneously. The probability of getting at least one head is
(A)`1/2`
(B)`1/8`
(C)`3/4`
(D)`7/8`
Solution
When two coins are tossed simultaneously, the possible outcomes are {(H, H), (H, T), (T, H), (T, T)}.
∴ Total number of outcomes = 4
Let E be the event of getting at least one head.
Then, the outcomes favourable to E are {(H, H), (H, T), (T, H)}.
∴ Number of favourable outcomes = 3
P(E) =\[\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}} = \frac{3}{4}\]
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