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Question
A father's age is three times the sum of the ages of his two children. After 5 years his age will be two times the sum of their ages. Find the present age of the father.
Solution
Let the sum of ages of two sons be x years
Age of man = 3x years
After 5 years age of the man = (3x + 5)years
Sum of ages of two sons =( x+10) years
Given, (3x+5)=2( x+10)
⇒ (3x+5) = 2x+ 20
⇒ x = 15
Hence 3x - 3(15) =45
Thus the age of the man(father) is 45 years.
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