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Question
Two equal sides of an isosceles triangle are 5y – 2 and 4y + 9 units. The third side is 2y + 5 units. Find ‘y’ and the perimeter of the triangle.
Solution
Given that 5y – 2 & 4y + 9 are the equal sides of an isosceles triangle.
∴ The 2 sides are equal
⇒ 5y – 2 = 4y + 9
∴5y – 4y = 9 + 2 ...(by transposing)
∴ y = 11
∴ 1st side = 5y – 2 = 5 × 11 – 2 = 55 – 2 = 53
2nd side = 53
3rd side = 2y + 5 = 2 × 11 + 5 = 22 + 5 = 27
Perimeter is the sum of all 3 sides
∴ P = 53 + 53 + 27 = 133 units
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|
S.No. |
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|
(a) |
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(b) |
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______ |
|
(f) |
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______ |
|
(g) |
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______ |
|
(h) |
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______ |
|
(i) |
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b = 4 |
______ |
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(j) |
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|
(k) |
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|
(l) |
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______ |
|
(m) |
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______ |
|
(n) |
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|
(o) |
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|
(p) |
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|
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