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Question
Two unbiased dice are thrown. Find the probability that the total of the numbers on the dice
is greater than 10.
Solution
When a pair of dice are thrown, then total no. of possible outcomes = 6 × 6 = 36
let E ⟶ event of getting sum on dice greater than 10
then no of favourable outcomes = 3 {(5, 6) (6, 5) (6, 6)}
we know that, P(E) =`"No.of favorable outcomes"/"Total no.of possible outcomes"`
i.e., P(E) =6/36 =1/6
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