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Question
Using identity, find the value of (100.1)2
Sum
Solution
(100.1)2 = (100 + 0.1)2
Substituting a = 100 and b = 0.1 in
(a + b)2 = a2 + 2ab + b2, we have
(100 + 0.1)2 = (100)2 + 2(100)(0.1) + (0.1)2
(100.1)2 = 10000 + 20 + 0.01
(100.1)2 = 10020.01
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Chapter 3: Algebra - Exercise 3.3 [Page 69]
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