Samacheer Kalvi solutions for Mathematics - Term 3 [English] Class 7 TN Board chapter 3 - Algebra [Latest edition]

(p – q)² = _______________

The product of (x + 5) and (x – 5) is ____________

The factors of x² – 4x + 4 are __________

Express 24ab²c² as product of its factors is ___________

(7x + 3)(7x – 4) = 49x² – 7x – 12

(a – 1)² = a² – 1

(x² + y²)(y² + x²) = (x² + y²)²

2p is the factor of 8pq

Express the following as the product of its factor

24 ab²c²

Express the following as the product of its factor

36 x³y²z

Express the following as the product of its factor

56 mn²p²

Using the identity (x + a)(x + b) = x² + x(a + b) + ab, find the following product

(x + 3)(x + 7)

Using the identity (x + a)(x + b) = x² + x(a + b) + ab, find the following product

(6a + 9)(6a – 5)

Using the identity (x + a)(x + b) = x² + x(a + b) + ab, find the following product

(4x + 3y)(4x + 5y)

Using the identity (x + a)(x + b) = x² + x(a + b) + ab, find the following product

(8 + pq)(pq + 7)

Expand the following square, using suitable identities

(2x + 5)²

Expand the following square, using suitable identities

(b – 7)²

Expand the following square, using suitable identities

(mn + 3p)²

Expand the following square, using suitable identities

(xyz – 1)²

Using the identity (a + b)(a – b) = a² – b², find the following product

(p + 2)(p – 2)

Using the identity (a + b)(a – b) = a² – b², find the following product

(1 + 3b)(3b – 1)

Using the identity (a + b)(a – b) = a² – b², find the following product

(4 – mn)(mn + 4)

Using the identity (a + b)(a – b) = a² – b², find the following product

(6x + 7y)(6x – 7y)

Evaluate the following, using suitable identity

51²

Evaluate the following, using suitable identity

103²

Evaluate the following, using suitable identity

998²

Evaluate the following, using suitable identity

47²

Evaluate the following, using suitable identity

297 × 303

Evaluate the following, using suitable identity

990 × 1010

Evaluate the following, using suitable identity

51 × 52

Simplify: (a + b)² – 4ab

Show that (m – n)² + (m + n)² = 2(m² + n²)

If a + b = 10 and ab = 18, find the value of a² + b²

Factorise the following algebraic expression by using the identity a² – b² = (a + b)(a – b)

z² – 16

Factorise the following algebraic expression by using the identity a² – b² = (a + b)(a – b)

9 – 4y²

Factorise the following algebraic expression by using the identity a² – b² = (a + b)(a – b)

25a² – 49b²

Factorise the following algebraic expression by using the identity a² – b² = (a + b)(a – b)

x⁴ – y⁴

Factorise the following using suitable identity

x² – 8x + 16

Factorise the following using suitable identity

y² + 20y + 100

Factorise the following using suitable identity

36m² + 60m + 25

Factorise the following using suitable identity

64x² – 112xy + 49y²

Factorise the following using suitable identity

a² + 6ab + 9b² – c²

If a + b = 5 and a² + b² = 13, then ab = ?

(5 + 20)(–20 – 5) = ?

The factors of x² – 6x + 9 are

The common factors of the algebraic expression ax²y, bxy² and cxyz is

Given that x ≥ y. Fill in the blank with suitable inequality sign

y `square` x

Given that x ≥ y. Fill in the blank with suitable inequality sign

x + 6 `square` y + 6

Given that x ≥ y. Fill in the blank with suitable inequality sign

x² `square` xy

Given that x ≥ y. Fill in the blank with suitable inequality sign

– xy `square` – y²

Given that x ≥ y. Fill in the blank with suitable inequality sign

x – y `square` 0

Linear inequation has almost one solution

When x is an integer, the solution set for x ≤ 0 are −1, −2, ...

An inequation, −3 < x < −1, where x is an integer, cannot be represented in the number line

x < − y can be rewritten as – y < x

Solve the following inequation

x ≤ 7, where x is a natural number

Solve the following inequation

x – 6 < 1, where x is a natural number

Solve the following inequation

2a + 3 ≤ 13, where a is a whole number

Solve the following inequation

6x – 7 ≥ 35, where x is an integer

Solve the following inequation

4x – 9 > – 33, where x is a negative integer

Solve the following inequation and represent the solution on the number line:

k > −5, k is an integer

Solve the following inequation and represent the solution on the number line:

−7 ≤ y, y is a negative integer

Solve the following inequation and represent the solution on the number line:

−4 ≤ x ≤ 8, x is a natural number.

Solve the following inequation and represent the solution on the number line:

3m – 5 ≤ 2m + 1, m is an integer

An artist can spend any amount between ₹ 80 to ₹ 200 on brushes. If cost of each brush is ₹ 5 and there are 6 brushes in each packet, then how many packets of brush can the artist buy?

The solutions set of the inequation 3 ≤ p ≤ 6 are (where p is a natural number)

The solution of the inequation 5x + 5 ≤ 15 are (where x is a natural number)

The cost of one pen is ₹ 8 and it is available in a sealed pack of 10 pens. If Swetha has only ₹ 500, how many packs of pens can she buy at the maximum?

The inequation that is represented on the number line as shown below is ____________

Using identity, find the value of (4.9)²

Using identity, find the value of (100.1)²

Using identity, find the value of (1.9) × (2.1)

Factorise: 4x² – 9y²

Simplify using identities

(3p + q)(3p + r)

Simplify using identities

(3p + q)(3p – q)

Show that (x + 2y)² – (x – 2y)² = 8xy

The pathway of a square paddy field has 5 m width and length of its side is 40 m. Find the total area of its pathway. (Note: Use suitable identity)

If X = a² – 1 and Y = 1 – b², then find X + Y and factorize the same

Find the value of (x – y)(x + y)(x² + y²)

Simplify (5x – 3y)² – (5x + 3y)²

Simplify: (a + b)² – (a – b)²

Simplify: (a + b)² + (a – b)²

A square lawn has a 2 m wide path surrounding it. If the area of the path is 136 m², find the area of lawn

Solve the following inequalities

4n + 7 ≥ 3n + 10, n is an integer

Solve the following inequalities

6(x + 6) ≥ 5(x – 3), x is a whole number

Solve the following inequalities

−13 ≤ 5x + 2 ≤ 32, x is an integer