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Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 7

Using the identity (x + a)(x + b) = x2 + x(a + b) + ab, find the following product (6a + 9)(6a – 5) - Mathematics

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Question

Using the identity (x + a)(x + b) = x2 + x(a + b) + ab, find the following product

(6a + 9)(6a – 5)

Sum

Solution

(6a + 9)(6a – 5)

Substituting x = 6a, a = 9 and b = – 5

In (x + a)(x + b) = x2 + x(a + b) + ab, we get

(6a + 9)(6a – 5) = (6a)2 + 6a(9 + (– 5)) + (9 × (– 5))

62a2 + 6a(4) + (– 45)

= 36a2 + 24a – 45

(6a + 9)(6a – 5) = 36a2 + 24a – 45

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Chapter 3: Algebra - Exercise 3.1 [Page 61]

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Samacheer Kalvi Mathematics - Term 3 [English] Class 7 TN Board
Chapter 3 Algebra
Exercise 3.1 | Q 4. (ii) | Page 61
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