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Question
Vehicles pass through a junction on a busy road at an average rate of 300 per hour. What is the expected number passing in two minutes?
Solution
In a poisson distribution
Average per hour = 300 vehicles
Mean per minute = `300/60` = 5
∴ λ = 5
P(X = 2) = `("e"^-5 (5)^2)/(2!)`
= `(("e"^-5(25))/2)`
= = e–5(12.5)
= 0.0067379 × 12.5
= 0.08422375
= 0.08422375 × 102
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