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Question
What happens when propanoic acid is warmed with methanol in the presence of a few drops of concentrated sulphuric acid? Write equation of the reaction involved.
Solution
When propanoic acid is warmed with methanol in the presence of a few drops of concentrated sulphuric acid in it, esterification takes place and an ester named methyl propanoate is formed along with water.
The chemical equation for the above reaction is:
C2H5COOH + CH3OH → C2H5COOCH3 + H2O.
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