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Question
What is the area of the largest triangle that can be fitted into a rectangle of length l units and width w units?
Options
`(lw)/2`
`(lw)/3`
`(lw)/6`
`(lw)/4`
Solution
`bb((lw)/2)`
Explanation:
Let ABCD be the rectangle of length l and width w.
Now, we construct a triangle of maximum area inside it in all possible ways.
∵ We know that,
Area of triangle = `1/2` × Base × Height
So, for maximum area, base and height of maximum, length is needed.
Here, maximum base length = `l`
And maximum height = w
∴ Area (maximum) of triangle = `1/2 xx l xx w = (l xx w)/2` sq.units
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