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Question
What will be the energy of each photon in monochromatic light of frequency 5 ×1014Hz?
Solution
Data: v = 5 x 1014 Hz, h = 6.63 x 10-34 J-s, 1eV = 1.6 x 10-19 J
The energy of each photon,
E = hv = (6.63 x 10-34 J-s)(5 x 1014 Hz)
= 3.315 × 10-19 J
`= (3.315 xx 10^-19 "J")/(1.6 xx 10^-19 "J"//"eV")`
= 2.072 eV
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