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Question
What would you observe in the following case:
Sugar crystals are added to a hard glass test tube containing concentrated sulphuric acid.
Solution
Charring of sugar takes place. Sulphuric acid dehydrates sugar, leaving behind carbon, which is black. Black charred residue is observed.
\[\ce{C12H22O11 -> \underset{Black charred residue}{11H2O}}\]
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