Advertisements
Advertisements
Question
Which of the following options are correct for \[\ce{[Fe(CN)6]^{3-}}\] complex?
(i) d2sp3 hybridisation
(ii) sp3d2 hybridisation
(iii) paramagnetic
(iv) diamagnetic
Solution
(i) d2sp3 hybridisation
(iii) paramagnetic
Explanation:
Electronic configuration Fe(26) = 1s2, 2s2, 2p6, 3s2, 3p6, 4s2, 3d6
CN− has a strong field ligand and electron pairing.
So, the number of the unpaired electron is 1 and paramagnetic.
APPEARS IN
RELATED QUESTIONS
For the complex [Fe(CN)6]3–, write the hybridization type, magnetic character and spin nature of the complex. (At. number : Fe = 26).
Write the hybridization and magnetic behaviour of the complex [Ni(CO)4].
(At.no. of Ni = 28)
Write the hybridization and shape of the following complexe : [CoF6]3–
(Atomic number : Co = 27, Ni = 28)
[NiCl4]2− is paramagnetic while [Ni(CO)4] is diamagnetic though both are tetrahedral. Why?
Explain [Co(NH3)6]3+ is an inner orbital complex whereas [Ni(NH3)6]2+ is an outer orbital complex.
Write the hybridisation and magnetic character of [Co(C2O4)3]3–.
(At. no. of Co = 27)
Why is [NiCl4]2− paramagnetic while [Ni(CN)4]2− is diamagnetic? (Atomic number of Ni = 28)
Write the hybridization type and magnetic behaviour of the complex [Ni(CN)4]2−. (Atomic number of Ni = 28)
Explain why \[\ce{[Fe(H2O)6]^{3+}}\] has magnetic moment value of 5.92 BM whereas \[\ce{[Fe(CN)6]^{3-}}\] – has a value of only 1.74 BM.
Why do compounds having similar geometry have different magnetic moment?
