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Question
Which one of the following has the highest bond order?
- N2
- N2+
- N2–
Solution
- N2
N2 = 14
σ1s2 σ1s*2 σ2s2 σ2s*2 π2py2 π2pz2 π2px2
Bond order = `6/2` = 3 - N2+
σ1s2 σ1s*2 σ2s2 σ2s*2 π2py2 π2pz2 π2px1
Bond order = `5/2` = 2.5 - N2–
σ1s2 σ1s*2 σ2s2 σ2s*2 π2py2 π2pz2 π2px*1
Bond order = `5/2` = 2.5
The highest bond order is N2.
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