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Question
While performing the experiment with raisins to determine the percentage of water absorbed by them, a student made following measurements:
Mass of water in the beaker = 40 g
Mass of raisins before soaking = 5 g
Mass of raisins after soaking for 2 hours = 8 g
Mass of water left in the beaker after the experiment = 35 g
The percentage of water absorbed by raisins is:
Options
`(40g-35g)/(35g)xx100`
`(40g-35g)/(40g)xx100`
`(8g-5g)/(8g)xx100`
`(8g-5g)/(5g)xx100`
Solution
Not in Current Syllabus
The percentage of water absorbed by raisins is calculated by using the formula
`(W_2-W_1)/(W_1)xx100`
where, W2 is the weight of wet resin and W1 is the weight of dry resin.
The Correct Answer is D
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