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Question
Without expanding determinants, find the value of `|(2014, 2017, 1),(2020, 2023, 1),(2023, 2026, 1)|`
Solution
Let D = `|(2014, 2017, 1),(2020, 2023, 1),(2023, 2026, 1)|`
Applying C2 → C2 – C1, we get
D = `|(2014, 3, 1),(2020, 3, 1),(2023, 3, 1)|`
Taking (3) common from C2, we get
D = `3|(2014, 1, 1),(2020, 1, 1),(2023, 1, 1)|`
= 3(0) ...[∵ C2 and C3 are identical]
= 0
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