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Question
Write preparation of propanone by using ethanoyl chloride and dimethyl cadmium.
Solution
When ethanoyl chloride is treated with dimethyl cadmium, propanone is formed as a product and cadmium chloride as a byproduct.
\[\ce{\underset{(Ethanoyl chloride)}{2CH3COCl} + \underset{(Dimethyl cadmium)}{(CH3)2Cd} ->\underset{Propanone}{2CH3 - CO - CH3} + \underset{(Cadmium chloride)}{CdCl2}}\]
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