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Question
Write the structure of the aldehyde, carboxylic acid and ester that yield 4-methylpent-2-en-1-ol.
Solution
1. Aldehyde yield 4-methylpent-2-en-1-ol is
\[\begin{array}{cc}
\ce{CH3 - CH - CH = CH - CHO}\\
|\phantom{...............}\\
\ce{CH3}\phantom{.............}
\end{array}\]
2. carboxylic acid yield 4-methylpent-2-en-1-ol is
\[\begin{array}{cc}
\ce{CH3 - CH - CH = CH - COOH}\\
|\phantom{.................}\\
\ce{CH3}\phantom{...............}
\end{array}\]
3. Ester yield 4-methylpent-2-en-1-ol is
\[\begin{array}{cc}
\ce{CH3 - CH - CH = CH - COOC2H5}\\
|\phantom{....................}\\
\ce{CH3}\phantom{..................}
\end{array}\]
The above shown compounds undergo a reduction reaction to yield 4-methylpent-2-en-1-ol
\[\begin{array}{cc}
\ce{CH3 - CH - CH = CH - CH2 - OH}\\
|\phantom{.....................}\\
\ce{CH3}\phantom{...................}
\end{array}\]
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