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Question
`x^2+12x+35=0`
Solution
Given:
`x^2+12x+35=0`
`⇒x^2+7x+5x+35=0`
`⇒ x(x+7)+5(x+7)=0`
`⇒(x+5)(x+7)=0`
`⇒x+5=0 or x+7=0`
`⇒x=-5 or x=-7`
Hence, -5 and -7 are the roots of the equation` x^2+12x+35=0`
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