Advertisements
Advertisements
Question
From the following equations, which one is the quadratic equation?
Options
`5/x - 3 = x^2`
x(x + 5) = 4
n – 1 = 2n
`1/x^2(x + 2) = x`
Solution
x(x + 5) = 4
Explanation:
Option: [A]
`5/x - 3 = x^2`
`(5 - 3x)/x = x^2`
5 – 3x = x3
x3 + 3x – 5 = 0
⇒ This is not a quadratic equation.
Option: [B]
x(x + 5) = 4
x2 + 5x = 4
x2 + 5x − 4 = 0
⇒ This is a quadratic equation.
Option: [C]
n − 1 = 2n
This is not a quadratic equation.
Option: [D]
`1/x^2 (x + 2) = x`
x + 2 = x3
x3 – (x + 2) = 0
x3 – x – 2 = 0
⇒ This is not a quadratic equation.
APPEARS IN
RELATED QUESTIONS
Verify whether 1 is the root of the quadratic equation : `x^2+3x-4=0`
If one root of the quadratic equation kx2 – 7x + 12 = 0 is 3, then find the value of k.
Check whether the following is quadratic equation or not.
x(x + 1) + 8 = (x + 2) (x - 2)
Solve : (x + 1)(2x + 8) = (x + 7)(x + 3)
(x + 3)² – 4(x + 3) – 5 = 0
Solve `(x - 3)/(x + 3) + (x + 3)/(x - 3) = 2 1/2`
Solve the following equation for x and give, in the following case, your answer correct to 3 decimal places:
3x2 – 12x – 1 = 0
Solve `((2x - 3)/(x -1)) - 4((x - 1)/(2x - 3)) = 3`
Solve `((3x + 1)/(x + 1)) + ((x + 1)/(3x + 1)) = 5/2`
Solve:
`2(x^2 + 1/x^2) - (x + 1/x) = 11`
Find the quadratic equation, whose solution set is:
{3, 5}
Without solving, comment upon the nature of roots of the following equation:
`x^2 + 2sqrt(3)x - 9 = 0`
`3sqrt(x/5)+3sqrt(5/x)=10`
`sqrt7x^2-6x-13sqrt7=0`
`3x^2-2sqrt6x+2=0`
The product of two consecutive natural numbers which are multiples of 3 is equal to 810. Find the two numbers.
Solve:
(x2 – 3x)2 – 16(x2 – 3x) – 36 = 0
In each of the following, determine whether the given numbers are solutions of the given equation or not: `x^2 - 3sqrt(3)x + 6 = 0; sqrt(3), -2sqrt(3)`
Solve the following equation by using formula:
`x - (1)/x = 3, x ≠ 0`
Solve the equation 5x2 – 3x – 4 = 0 and give your answer correct to 3 significant figures: