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प्रश्न
`3x^2-2sqrt6x+2=0`
उत्तर
The given equation is `3x^2-2sqrt6x+2=0`
Comparing it with `ax^2+bx+c=0`
`a=3,b=-sqrt2 and c=2`
∴ Discriminant, D=b^2-4ac=`(-2sqrt6)^2-4xx3xx2=24-24=0`
So, the given equation has real roots.
Now,
∴α= `(-b+sqrt(D))/(2a)=-(-2sqrt(6)+0)/(2xx3)=(2sqrt6)/6=sqrt6/3`
β= `(-b-sqrt(D))/(2a)=-(-2sqrt(6))/(2xx3)=(2sqrt6)/6=sqrt6/3`
Hence, `sqrt6/3` are the repeated of the given equation.
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