Advertisements
Advertisements
प्रश्न
A, B and C have co-ordinates (0, 3), (4, 4) and (8, 0) respectively. Find the equation of the line through A and perpendicular to BC.
उत्तर
Slope of BC = `(0 - 4)/(8 - 4) = (-4)/4 = -1`
Slope of line perpendicular to BC = `(-1)/"slope of BC" = 1`
The equation of the line through A and perpendicular to BC is given by:
y − y1 = m(x − x1)
y − 3 = 1(x − 0)
y − 3 = x
y = x + 3
APPEARS IN
संबंधित प्रश्न
If the straight lines 3x – 5y = 7 and 4x + ay + 9 = 0 are perpendicular to one another, find the value of a.
Find, which of the following points lie on the line x – 2y + 5 = 0 :
(1, 3)
State, true or false :
The line `x/2 + y/3 = 0` passes through the point (4, −6).
The line y = 3x – 2 bisects the join of (a, 3) and (2, −5), find the value of a.
A line intersects x-axis at point (−2, 0) and cuts off an intercept of 3 units from the positive side of y-axis. Find the equation of the line.
Write down the equation of the line whose gradient is `3/2` and which passes through P, where P divides the line segment joining A(−2, 6) and B(3, −4) in the ratio 2 : 3.
A and B are two points on the x-axis and y-axis respectively. P(2, −3) is the mid point of AB. Find the
- co-ordinates of A and B
- slope of line AB
- equation of line AB.
The line 5x - 3y +1 = 0 divides the join of (2,m) and (7,9) in the ratio 2: 3. Find the value of m.
Find the equation of a line passing through (3, – 2) and perpendicular to the line.
x - 3y + 5 = 0.
Find the equation of a line parallel to 2y = 6x + 7 and passing through (–1, 1).