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Question
A, B and C have co-ordinates (0, 3), (4, 4) and (8, 0) respectively. Find the equation of the line through A and perpendicular to BC.
Solution
Slope of BC = `(0 - 4)/(8 - 4) = (-4)/4 = -1`
Slope of line perpendicular to BC = `(-1)/"slope of BC" = 1`
The equation of the line through A and perpendicular to BC is given by:
y − y1 = m(x − x1)
y − 3 = 1(x − 0)
y − 3 = x
y = x + 3
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