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The line y = 3x – 2 bisects the join of (a, 3) and (2, −5), find the value of a. - Mathematics

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Question

The line y = 3x – 2 bisects the join of (a, 3) and (2, −5), find the value of a.

Sum

Solution

The given line bisects the join of A(a, 3) and B(2, −5), so the co-ordinates of the mid-point of AB will satisfy the equation of the line.

The co-ordinates of the mid-point of AB are 

`((a + 2)/2, (3 - 5)/2)`

= `((a + 2)/2, (-2)/2)`

= `((a + 2)/2, -1)`

Substituting `x = (a + 2)/2 ` and y = –1 in the given equation, we have:

y = 3x – 2

`-1 = 3 xx (a + 2)/2 - 2`

`3 xx (a + 2)/2 = 1`

`a + 2 = 2/3`

`a = 2/3 - 2`

= `(2 - 6)/3`

= `(-4)/3`

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Equation of a Line
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Chapter 14: Equation of a Line - Exercise 14 (A) [Page 186]

APPEARS IN

Selina Mathematics [English] Class 10 ICSE
Chapter 14 Equation of a Line
Exercise 14 (A) | Q 7.1 | Page 186
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