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A cell of e.m.f. ε and internal resistance 𝔯 sends current 1.0 A when it is connected to an external resistance 1.9 Ω. But it sends current 0.5 A when it is connected to an external resistance 3.9 Ω. - Physics

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प्रश्न

A cell of e.m.f. ε and internal resistance 𝔯 sends current 1.0 A when it is connected to an external resistance 1.9 Ω. But it sends current 0.5 A when it is connected to an external resistance 3.9 Ω. Calculate the values of ε and 𝔯.

संख्यात्मक

उत्तर

In first case

I = 1 A, R = 1.9 ohm

ε = I (R + r)

= 1(1.9 + r)

ε = 1.9 + r   ...(1)

In second case

I = 0.5 A, R = 3.9 ohm

ε = I(R + r)

= 0.5 (3.9 + r)

ε = 1.95 + 0.5r   ...(2)

From eq. (1) and (2),

1.9 + r = 1.95 + 0.5r

r = `0.05/0.5`

r = 0.1 ohm

Substituting value of r

ε = 1.9 + r

= 1.9 + 0.1

= 2 V

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Internal Resistance of a Cell
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अध्याय 8: Current Electricity - Exercise 8 (B) 3 [पृष्ठ २०१]

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सेलिना Physics [English] Class 10 ICSE
अध्याय 8 Current Electricity
Exercise 8 (B) 3 | Q 5 | पृष्ठ २०१

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