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Define the E.M.F. (E) of a Cell and the Potential Difference (V) of a Resistor R in Terms of the Work Done in Moving a Unit Charge. - Physics

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प्रश्न

Define the e.m.f. (E) of a cell and the potential difference (V) of a resistor R in terms of the work done in moving a unit charge. State the relation between these two works and the work done in moving a unit charge through a cell connected across the resistor. Take the internal resistance of the cell as ‘r’. Hence obtain an expression for the current i in the circuit.

संक्षेप में उत्तर

उत्तर

E. M. F. of a cell is generally defined as the amount of work done (or the energy spent) in taking a unit positive charge around the complete circuit of the cell (i.e., in the wire outside the cell and the electrolyte within the cell). It is also defined as the potential difference between the terminals of a cell when no current is drawn from it (or when the cell is in open circuit).

Potential difference (p.d.) or the terminal voltage of a cell is generally defined as the amount of work done in carrying a unit positive charge round the circuit connected across the terminals of the cell. If W is the amount of work done (in J) in moving a test charge q between the terminals of a cell through a resistor R, then the p.d. i.e., work done in moving a unit positive charge across the terminals of the cell.
Relation between E, V (p.d.), external resistance R and the internal resistance r’,

Applying Ohm's law to external resistance only

I = `"V"/"R"`      .....(i)

Again applying Ohm's law to complete circuit

I = `"E"/("R" + "r")`   ....(ii)

Comparing I in (i) and (ii), We have

`"V"/"R" = "E"/("R" + "r")`

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Internal Resistance of a Cell
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अध्याय 7: Electricity - Figure Based Long Answers

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आईसीएसई Physics [English] Class 10
अध्याय 7 Electricity
Figure Based Long Answers | Q 1

संबंधित प्रश्न

Explain why the p.d across the terminals of a cell is more in an open circuit and reduced in a closed circuit. 


A cell is used to send current to an external circuit.

  1. How does the voltage across its terminals compare with its e.m.f.?
  2. Under what condition is the e.m.f. of a cell equal to its terminal voltage? 

The diagram below in Fig. 8.40 shows a cell of e.m.f. ε = 2 volt and internal resistance r = 1 ohm to an external resistance R = 4 ohm. The ammeter A measures the current in the circuit and the
voltmeter V measures the terminal voltage across the cell. What will be the readings of the ammeter and voltmeter when (i) the key K is open, (ii) the key K is closed. 

  


A battery of e.m.f 3.0 V supplies current through a circuit in which the resistance can be changed.
A high resistance voltmeter is connected across the battery. When the current is 1.5 A, the voltmeter reads 2.7 V. Find the internal resistance of the battery. 


A cell of e.m.f. 1.8V and internal resistance 2Ω is connected in series with an ammeter of resistance 0.7Ω and a resistor of 4.5Ω as shown in Fig. 

  1. What would be the reading of the ammeter?
  2. What is the potential difference across the terminals of the cell? 

What is the colour code for the insulation on the earth wire?


Four cells, each of e.m.f. 1.5 V and internal resistance 2.0 ohms are connected in parallel. The battery of cells is connected to an external resistance of 2.5 ohms. Calculate:

(i) The total resistance of the circuit.
(ii) The current flowing in the external circuit.
(iii) The drop in potential across-the terminals of the cells.


A cell supplies a current of 0.6 A through a 2Ω coil and a current of 0.3 A through on 8Ω coil. Calculate the e.m.f and internal resistance of the cell.


The diagram in Figure shows a cell of e.m.f. ε = 4 volt and internal resistance r = 2 ohm connected to an external resistance R = 8 ohm. The ammeter A measures the current in the circuit and the voltmeter V measures the terminal voltage across the cell. What will be the readings of the ammeter and voltmeter when

  1. the key K is open, and
  2. the key K is closed


A battery of e.m.f. 6·0 V supplies current through a circuit in which the resistance can be changed. A high resistance voltmeter is connected across the battery. When the current is 3 A, the voltmeter reads 5.4 V. Find the internal resistance of the battery.


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