Advertisements
Advertisements
प्रश्न
A circular racing track has inner circumference 528 m and outer circumference 616 m. Find the width of the track.
उत्तर
Outer circumference = 616 m
Radius (R) = `"C"/(2π)=(616xx7)/(2xx22)"m"` = 98 m
Inner circumference = 528 m
∴ Inner radius (r) =`(528xx7)/(2xx22)"m"` = 84 m
∴ Width of track = R − r = 98 − 84 = 14 m
APPEARS IN
संबंधित प्रश्न
Find the area of circle whose circumference is 44 cm.
Diagonal of a square is 20 cm. Find the length and perimeter of the square.
Find the diameter of the circle whose area is equal to the sum of the areas of two circles having radii 4 cm and 3 cm.
Four equal circles are described about the four corners of a square so that each touches two of the others, as shown in the figure. Find the area of the shaded region, if each side of the square measures 14 cm.
Diameter of the circular garden is 42 m. There is a 3.5 m wide road around the garden. Find the area of the road.
The area of a circular ring enclosed between two concentric circles is 88 cm 2. Find the radii of the two circles, if their difference is 1 cm.
A wire is in the form of a circle of radius 42 cm. It is bent into a square.
Determine the side of the square and compare the area of the regions enclosed in two cases.
In the given figure, the area of the shaded portion is 770 cm2. If the circumference of the outer circle is 132 cm, find the width of the shaded portion.
Find the area and perimeter of the following semicircles: Diameter = 7cm
The diameter of a wheel is 1.26 m. The distance traveled in 500 revolutions is ____________.
