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प्रश्न
A coil has a self-inductance of 0·05 Henry. Find the magnitude of the emf induced in it when the current flowing through it is changing at the rate of 100 As-1.
उत्तर
L = 0.05H
`("dI")/"dt" = 100`AS-1
`|"E"| = "L"("dI")/"dt" = 5/100 xx 100`
= 5V
∴ Magnitude of induced emf is 5V.
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संबंधित प्रश्न
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