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A Cylindrical Container of Radius 6 Cm and Height 15 Cm is Filled with Ice-cream. the Whole Ice-cream Has to Be Distributed to 10 Children in Equal Cones with Hemispherical - Mathematics

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प्रश्न

A cylindrical container of radius 6 cm and height 15 cm is filled with ice-cream. The whole ice-cream has to be distributed to 10 children in equal cones with hemispherical tops. If the height of the conical portion is 4 times the radius of its base, then find the radius of the ice-cream cone.

योग

उत्तर

We have 

the base radius of the cylindrical containers, R=6 cm,

the height of the container, H = 15 cm,

Let the base radius and the height of the ice-cream cone be r an 

Also, h = 4r

Now, the volume of the cylindrical container = πR2H

`= 22/7xx6xx6xx15`

`= 11880/7` cm

`rArr "the volume of the ice -cream distributed to 10 children" = 11880/7 cm`

`rArr 10xx "Volume of a ice - creame cone = 11880/7" `

`rArr 10xx ("Volume of the cone + Volume of the hemisphere") = 11880/7`

`rArr 10xx(1/3 pir^2h + 2/3 pir^3) = 11880/7`

`rArr 10xx(1/3pir^2hxx4r + 2/3pir^3)= 11880/7`

`rArr 10xx(1/3pir^2xx4r+2/3pir^3)= 11880/7`

`rArr 10xx(6/3pir^3)=11880/7`

`rArr 10xx2xx22/7xxr^3 = 11880/7`

`rArr r^3 = (11880xx7)/(7xx10xx2xx22)`

`rArr r^3 = 27`

`rArr r = root(3)(27)`

∴ r = 3 cm

So, the radius of the ice-cream cone is 3 cm.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 19: Volume and Surface Area of Solids - Exercise 19A [पृष्ठ ८७५]

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आरएस अग्रवाल Mathematics [English] Class 10
अध्याय 19 Volume and Surface Area of Solids
Exercise 19A | Q 16 | पृष्ठ ८७५

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