Advertisements
Advertisements
प्रश्न
A farmer has enough food to feed 20 animals in his cattle for 6 days. How long would the food last if there were 10 more animals in his cattle?
उत्तर
Let the food last for x days. According to question,
| Number of days | 6 | x |
| Number of animals | 20 | 30 |
Since the given problem is in inverse proportion.
∴ 6 × 20 = x × 30
⇒ `(6xx20)/30` = x
⇒ 4 = x
Therefore, the required number of days is 4.
APPEARS IN
संबंधित प्रश्न
Which of the following are in inverse proportion?
The time taken for a fixed journey and the speed of the vehicle.
A car takes 2 hours to reach a destination by travelling at the speed of 60 km/h. How long will it take when the car travels at the speed of 80 km/h?
In a hostel of 50 girls, there are food provisions for 40 days. If 30 more girls join the hostel, how long will these provisions last?
55 cows can graze a field in 16 days. How many cows will graze the same field in 10 days?
If x and y vary inversely as other and x = 30, find y when constant of variation = 900.
12 cows can graze a field for 10 days. 20 cows can graze the same field for _______ days
Six men can complete a work in 12 days. Two days later, 6 more men joined them. How many days will they take to complete the remaining work?
When two quantities x and y are in ______ proportion or vary ______ they are written as `x oo 1/y`.
Find the values of x and y if a and b are in inverse proportion:
- 12 x 8
- 30 5 y
