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प्रश्न
A long straight conductor kept along X' X axis, carries a steady current I along the +x direction. At an instant t, a particle of mass m and charge q at point (x, y) moves with a velocity `vecv` along +y direction. Find the magnitude and direction of the force on the particle due to the conductor.
उत्तर
From relation,
`vecF = qvB[(-hati) xx (hatk)]`
`vecF = qvBhatj`
According to Fleming's left-hand rule, the magnetic field will point in a direction that is (x) inside the paper's plane. Therefore, the force will be applied in the conductor's direction of travel. Therefore, the force will be exerted in the +y direction.
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