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A Mass of 6 × 1024 Kg (Equal to the Mass of the Earth) is to Be Compressed in a Sphere in Such a Way that the Escape Velocity - Physics

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प्रश्न

A mass of 6 × 1024 kg (equal to the mass of the earth) is to be compressed in a sphere in such a way that the escape velocity from its surface is 3 × 108 m s−1. What should be the radius of the sphere?

योग

उत्तर

Mass of the sphere = 6 × 1024 kg
Escape velocity = 3 × 108 m/s

Escape velocity is given by

\[v_e = \frac{2GM}{R}\]

\[ \Rightarrow R = \frac{2GM}{{v_e}^2}\]

\[ = \frac{2 \times 6 . 67 \times {10}^{- 11} \times 6 \times {10}^{24}}{\left( 3 \times {10}^8 \right)^2}\]

\[ = \frac{2 \times 40 . 02 \times {10}^{13}}{9 \times {10}^{16}}\]

\[ = \frac{80 . 02}{9} \times {10}^{- 3} m\]

\[ = 8 . 89 \times {10}^{- 3} m\]

\[ = 9 \ \text { mm }\]

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अध्याय 11: Gravitation - Exercise [पृष्ठ २२७]

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एचसी वर्मा Concepts of Physics Vol. 1 [English] Class 11 and 12
अध्याय 11 Gravitation
Exercise | Q 39 | पृष्ठ २२७

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