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प्रश्न
Arrange the following:
In decreasing order of basic strength in the gas phase:
C2H5NH2, (C2H5)2NH, (C2H5)3N and NH3
उत्तर
In the gas phase, there is no solvation effect. As a result, the basic strength mainly depends upon the +I effect. The higher the +I effect, the stronger is the base. Also, the greater the number of alkyl groups, the higher is the +I effect. Therefore, the given compounds can be arranged in the decreasing order of their basic strengths in the gas phase as follows:
(C2H5)3N > (C2H5)2NH > C2H5NH2 > NH3
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संबंधित प्रश्न
Arrange the following:
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C6H5NH2, C2H5NH2, (C2H5)2NH2, NH3
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(I)
(II)
(III)
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\[\ce{C6H5NH2, C6H5NHCH3, C6H5CH2NH2, CH3NH2, NH3}\]
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