Advertisements
Advertisements
प्रश्न
Arrange the following in the increasing order of their boiling point and give a reason for your ordering.
Butan-2-ol, Butan-1-ol, 2-methyl propane-2-ol
उत्तर
Boiling points increase regularly as the molecular mass increases due to a corresponding increase in their Van der Waal's force of attraction. Among isomeric alcohols, 2° alcohols have lower boiling points than 1° alcohol due to a corresponding decrease in the extent of H-bonding because of steric hindrance. Thus the boiling point of Butan-2-ol is lower than that of Butan-1-ol. Overall increasing order of boiling points is, 2-methyl propane-2-ol < Butan-2-ol < Butan-1-ol.
APPEARS IN
संबंधित प्रश्न
on treatment with Con. H2SO4 predominately gives
Which one of the following will react with phenol to give salicylaldehyde after hydrolysis.
Predict the major product, when 2-methyl-but-2-ene is converted into alcohol in the following method.
Hydroxylation using bayers reagent
Can we use nucleophiles such as NH3, CH3O for the Nucleophilic substitution of alcohols?
Complete the following reaction.
\[\ce{C6H5 - OH ->[Zn dust] A ->[CH3Cl][Anhydrous AlCl3] B ->[acid KMnO4] C}\]
What will be the product (X and A) for the following reaction?
\[\ce{acetylchloride ->[i) CH3MgBr][ii) H3O^+] X ->[acid K2Cr2O7] A}\]
3, 3-dimethyl butane-2-ol on treatment with conc. H2SO4 to give tetramethyl ethylene as a major product. Suggest a suitable mechanism.
\[\begin{array}{cc}\phantom{..........}\ce{CH3}\\\phantom{.......}/\\\ce{C6H4}\\
\phantom{.......}\backslash\\\phantom{.........}\ce{OH}\end{array}\] is a/an ______.
What will be the product (X and A) for the following reaction?
acetylchloride \[\ce{->[i) CH3MgBr][ii) H3O+] X ->[acid K2Cr2O7] A}\]
What will be the product (X and A) for the following reaction.
\[\ce{acetylchloride ->[i) CH3MgBr][ii) H3O^+] X ->[acid K2Cr2O7] A}\]
