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प्रश्न
At particular temperature Kc = 4 × 10-2 for the reaction, \[\ce{H2S (g) <=> H2(g) +1/2 S2(g)}\]. Calculate the Kc for the following reaction.
\[\ce{3H2S (g) <=> 3H2 (g) + 3/2 S2 (g)}\]
उत्तर
KC = 4 x 10-2 for the reaction
\[\ce{3H2S (g) <=> 3H2 (g) + 3/2 S2 (g)}\]
`"K"_"C" = (["H"_2]["S"_2]^(1/2))/(["H"_2"S"]) = 4 xx 10^-2`
For the reaction,
\[\ce{2H2S (g) <=> 2H2 (g) + S2 (g)}\]
`"K"_"C" = (["H"_2]^3["S"_2]^(3/2))/(["H"_2"S"]^3) = (4 xx 10^-2)^3`
= 64 × 10-6
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