Advertisements
Advertisements
प्रश्न
Calculate the angles x, y and z if :
`x/3 = y/4 = z/5`
उत्तर
Let x = 3k, y = 4k and z = 5k
∠ADC = x + z = 8k and ∠ABC = x + y = 7k
(Exterior angle of a ∆ is equal to the sum of pair of interior opposite angles)
Also, ∠ABC + ∠ADC = 180°
(Pair of opposite angles in a cyclic quadrilateral are supplementary)
`=>` 8k + 7k = 180°
`=>` 15k = 180°
∴ `k = 180^circ/15 = 12^circ`
∴ x = 3 × 12° = 36°
y = 4 × 12° = 48°
z = 5 × 12° = 60°
APPEARS IN
संबंधित प्रश्न
In the figure given alongside, AB and CD are straight lines through the centre O of a circle. If ∠AOC = 80° and ∠CDE = 40°, find the number of degrees in:
- ∠DCE,
- ∠ABC.
Two chords AB and CD intersect at P inside the circle. Prove that the sum of the angles subtended by the arcs AC and BD at the centre O is equal to twice the angle APC.
In the given figure, AB = AC = CD and ∠ADC = 38°. Calculate :
- Angle ABC
- Angle BEC
The given figure shows a circle with centre O such that chord RS is parallel to chord QT, angle PRT = 20° and angle POQ = 100°. Calculate:
(ii) angle QRP
The given figure shows a circle with centre O such that chord RS is parallel to chord QT, angle PRT = 20° and angle POQ = 100°. Calculate:
(iii) angle QRS
The given figure shows a circle with centre O such that chord RS is parallel to chord QT, angle PRT = 20° and angle POQ = 100°. Calculate:
(iv) angle STR
In the given figure, O is the center of the circle and the length of arc AB is twice the length of arc BC. If ∠AOB = 100°,
find: (i) ∠BOC (ii) ∠OAC
In the given figure, AB = BC = DC and ∠AOB = 50°.
(i) ∠AOC
(ii) ∠AOD
(iii) ∠BOD
(iv) ∠OAC
(v) ∠ODA
In the given figure, AB is a side of regular pentagon and BC is a side of regular hexagon.
(i) ∠AOB
(ii) ∠BOC
(iii) ∠AOC
(iv) ∠OBA
(v) ∠OBC
(vi) ∠ABC
C is a point on the minor arc AB of the circle, with centre O. Given ∠ACB = p°, ∠AOB = q°.
(i) Express q in terms of p.
(ii) Calculate p if ACBO is a parallelogram.
(iii) If ACBO is a parallelogram, then find the value of q + p.