Advertisements
Advertisements
प्रश्न
Compute the median for the following data:
| Marks | No. of students |
| Less than 10 | 0 |
| Less than 30 | 10 |
| Less than 50 | 25 |
| Less than 70 | 43 |
| Less than 90 | 65 |
| Less than 110 | 87 |
| Less than 130 | 96 |
| Less than 150 | 100 |
उत्तर
| Marks | No. of students | Class internal | Frequency | Cumulative frequency |
| Less than 10 | 0 | 0 – 10 | 0 | 0 |
| Less than 30 | 10 | 10 – 30 | 10 | 10 |
| Less than 50 | 25 | 30 – 50 | 15 | 25 |
| Less than 70 | 43 | 50 – 70 | 18 | 43 |
| Less than 90 | 65 | 70 – 90 | 22 | 65 |
| Less than 110 | 87 | 90 – 110 | 22 | 87 |
| Less than 130 | 96 | 110 – 130 | 9 | 96 |
| Less than 150 | 100 | 130 – 150 | 8 | 100 |
| N = 100 |
We have N = 100
`N/2=100/2=50`
The commutative frequencies just greater than N/2 is 65 then median class is 70 – 90
such that l = 70, f = 22, h = 90 – 70 = 20 and F = 43
Median `=l+(N/2-F)/fxxh`
`=70+(50-43)/22xx20`
`=70+(7xx20)/22`
`=70+140/22`
= 70 + 6.36
= 76.36
APPEARS IN
संबंधित प्रश्न
Compute the median for the following data:
| Marks | No. of students |
| More than 150 | 0 |
| More than 140 | 12 |
| More than 130 | 27 |
| More than 120 | 60 |
| More than 110 | 105 |
| More than 100 | 124 |
| More than 90 | 141 |
| More than 80 | 150 |
Calculate the missing frequency from the following distribution, it being given that the median of distribution is 24.
| Class | 0 – 10 | 10 – 20 | 20 – 30 | 30 – 40 | 40 - 50 |
| Frequency | 5 | 25 | ? | 18 | 7 |
Find the correct answer from the alternatives given.
| Distance Covered per litre (km) | 12 - 14 | 14 - 16 | 16 - 18 | 18 - 20 |
| No. of cars | 11 | 12 | 20 | 7 |
The median of the distances covered per litre shown in the above data is in the group . . . . . .
The median of the following data is 50. Find the values of p and q, if the sum of all the frequencies is 90.
| Marks: | 20 -30 | 30-40 | 40-50 | 50-60 | 60-70 | 70-80 | 80-90 |
| Frequency: | P | 15 | 25 | 20 | q | 8 | 10 |
For the following distribution
| Marks | 0 - 10 | 10 - 20 | 20 - 30 | 30 - 40 | 40 - 50 |
| No. of Students | 3 | 9 | 13 | 10 | 5 |
the number of students who got marks less than 30 is?
Consider the data:
| Class | 65 – 85 | 85 – 105 | 105 – 125 | 125 – 145 | 145 – 165 | 165 – 185 | 185 – 205 |
| Frequency | 4 | 5 | 13 | 20 | 14 | 7 | 4 |
The difference of the upper limit of the median class and the lower limit of the modal class is:
Heights of 50 students of class X of a school are recorded and following data is obtained:
| Height (in cm) | 130 – 135 | 135 – 140 | 140 – 145 | 145 – 150 | 150 – 155 | 155 – 160 |
| Number of students | 4 | 11 | 12 | 7 | 10 | 6 |
Find the median height of the students.
The median of the following frequency distribution is 25. Find the value of x.
| Class: | 0 – 10 | 10 – 20 | 20 – 30 | 30 – 40 | 40 – 50 |
| Frequency: | 6 | 9 | 10 | 8 | x |
Find the median of the following frequency distribution:
| Class: | 0 – 20 | 20 – 40 | 40 – 60 | 60 – 80 | 80 – 100 |
| Frequency: | 6 | 8 | 5 | 9 | 7 |
If in a frequency distribution, the mean and median are 21 and 22 respectively, then its mode is approximately ______.
