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Derive the expression for total acceleration in the non-uniform circular motion. - Physics

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प्रश्न

Derive the expression for total acceleration in the non-uniform circular motion.

व्युत्पत्ति

उत्तर

If the speed of the object in circular motion is not constant, then we have non-uniform circular motion. For example, when the bob attached to a string moves in a vertical circle, the speed of the bob is not the same at all times. Whenever the speed is not the same in a circular motion, the particle will have both centripetal and tangential acceleration as shown in the figure.

Resultant acceleration (aR) in a non-uniform circular motion 

The resultant acceleration is obtained by the vector sum of centripetal and tangential acceleration Since centripetal acceleration is `v^2/r`, the magnitude of this resultant acceleration is given by `-a_R = sqrt(a_t^2 + (v^2/r)^2)`

This resultant acceleration makes an angle 0 with the radius vector as shown in the figure.
This angle is given by tan θ = `a_t/((v^2"/"r))`

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Concept of Rest and Motion
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अध्याय 2: Kinematics - Evaluation [पृष्ठ १००]

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सामाचीर कलवी Physics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 2 Kinematics
Evaluation | Q III. 7. | पृष्ठ १००
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